3[x-1]+x=4[x+2]

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Solution for 3[x-1]+x=4[x+2] equation:


Simplifying
3[x + -1] + x = 4[x + 2]

Reorder the terms:
3[-1 + x] + x = 4[x + 2]
[-1 * 3 + x * 3] + x = 4[x + 2]
[-3 + 3x] + x = 4[x + 2]

Combine like terms: 3x + x = 4x
-3 + 4x = 4[x + 2]

Reorder the terms:
-3 + 4x = 4[2 + x]
-3 + 4x = [2 * 4 + x * 4]
-3 + 4x = [8 + 4x]

Add '-4x' to each side of the equation.
-3 + 4x + -4x = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
-3 + 0 = 8 + 4x + -4x
-3 = 8 + 4x + -4x

Combine like terms: 4x + -4x = 0
-3 = 8 + 0
-3 = 8

Solving
-3 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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